请问QTOUCH qt_touch_status问题
我才接触QTOUCH时间不长，这段时间看DEMO程序有点不明白：send_debug_byte( 'O' );
send_debug_byte( 'N' );
maskbit = ((uint8_t *) &qt_touch_status);
send_debug_byte( ' ' );
send_debug_byte( '0' );
send_debug_byte( 'x' );
send_debug_byte( HexTable );
send_debug_byte( HexTable );
DEMO里的和PC超级终端通信的这部分，意思应该是输出ON ,OX...
就是
maskbit = ((uint8_t *) &qt_touch_status);这里不太看的懂，
定义是这样定义的
typedef struct tag_qt_touch_status_t
{
/*
* The state (on/off) of the library sensors.
* Bit 'n' = state of sensor 'n'.
* Bit 0 = sensor_states bit 0
* Bit 1 = sensor_states bit 1
* ...
* Bit 7 = sensor_states bit 7
* Bit 8 = sensor_states bit 0
* Bit 9 = sensor_states bit 1
* ... etc
* 0 = not in detect, 1 = in detect.
*/
uint8_t sensor_states;
/*
* Rotor angles or slider positions.
* These values are valid when sensor_states shows that the corresponding
* rotor or slider sensor is in detect.
*/
uint16_t rotor_slider_values;
} qt_touch_status_t;
不大明白((uint8_t *) &qt_touch_status); 这里【1】指向谁了
qt_touch_status本身应该是结构体啊 没看到是结构体数组啊？
2.我的项目是用的是圆盘 ，根据圆盘触摸滑动去控制LED灯，那么我应该是读rotor_slider_values的值去判断，小弟不明白这个值是什么、我的精度是256那么我理解的是这个值该是在0-0XFF，可是我怎么好像看资料上说是个角度呢？
新手还请大家多多指点 ，谢谢 小弟还想请问下
硬件布板上 QTOUCH，圆盘中间有个按键，这个触摸感应按键的线怎么从大圆走出来呢 。。。
请懂的朋友 指导指导
页:
[1]