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吸取各位前辈的经验，将之前二极管用量多的问题优化一下，目前不用二极管能接6键，2只二极管能接12键，6只二极管能接18键，9只二极管能接21键，第22键要单独占用3只二极管最不化算。
实验用89S51作试验，电路接线就是P1.2,P1.3,P1.4接键盘，P1.0接显示器。
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/*==================================================================*
* 3个IO接识别22键测试程序 *
* ------------------------------------------------ *
* MCU: AT89C2051 *
* OSC: 12M cysytel *
* 程序设计:Cowboy *
* 程序版本:V1.0 *
*==================================================================*/
#include <reg52.h>
//================== IO口线连接 ==================
sbit Bus = P1^0;
sbit IO_a = P1^4;
sbit IO_b = P1^3;
sbit IO_c = P1^2;
//================== 变量声明 ====================
unsigned char Disp_buf[3];
unsigned char Dig;
unsigned char Key_count;
unsigned char bdata Key_state;
sbit KB0 = Key_state^0;
sbit KB1 = Key_state^1;
sbit KB2 = Key_state^2;
sbit KB3 = Key_state^3;
sbit KB4 = Key_state^4;
sbit KB5 = Key_state^5;
//================== 表格数据 ====================
code unsigned char LED_font[24]=
{
0x84,0x9f,0xa2,0x8a,0x99,0xc8,0xc0,0x9e,0x80, //012345678
0x88,0x90,0xc1,0xe4,0x83,0xe0,0xf0,0xff,0xfb, //9abcdef -
};
code unsigned char Key_tab[64]= //键码映射表
{// 0 1 2 3 4 5 6 7 8 9
22, 0, 2, 0, 0, 0, 0, 0, 4, 0, //0
0, 0, 0, 0, 0,18, 0, 0, 0, 0, //1X
0, 0, 0, 0, 0, 0, 3,14, 0, 0, //2X
20,10, 6, 0, 0, 0, 0, 0, 1,19, //3X
0, 5, 0, 0, 0,15, 0,11, 0, 0, //4X
0,17, 0, 0,13, 8, 0,21, 0, 9, //5X
16,12, 7, 0 //6X
};
//=============== 检测按键 =================
void Key_scan()
{
unsigned char i;
Key_count --; //扫描次序
Key_count &= 3;
switch (Key_count) //按次序处理
{
case 2: //第一轮扫描
KB0 = IO_b;
KB1 = IO_c;
IO_a = 1;
IO_b = 0;
break;
case 1: //每二轮扫描
KB2 = IO_c;
KB3 = IO_a;
IO_b = 1;
IO_c = 0;
break;
case 0: //每三轮扫描
KB4 = IO_a;
KB5 = IO_b;
IO_c = 1;
break;
default: //每四轮扫描
if (!IO_a) KB0 = 0;
if (!IO_b) KB2 = 0;
if (!IO_c) KB4 = 0;
IO_a = 0;
//======更新显示缓冲区=======
i = Key_tab[Key_state];
if (i == 0)
{
Disp_buf[2] = 0x11; //显示三横
Disp_buf[1] = 0x11;
Disp_buf[0] = 0x11;
}
else
{
Disp_buf[2] = 0x0c; //字符"C"
Disp_buf[1] = i / 10; //键码十位
Disp_buf[0] = B;于 //键码个位
}
Key_state = 0;
}
}
/*===================================================================
ONE WIRE 显示总线驱动程序
===================================================================*/
//=============== 发送一位 =================
void Send_bit(bit Dat)
{
unsigned char i = 3;
if (!Dat) Bus = 0;
else
{
Bus = 0;
Bus = 1;
}
while(--i); //延时8us
Bus = 1;
}
//=============== 总线驱动 =================
void Bus_drive()
{
unsigned char i = 0;
unsigned char Sdat;
Send_bit(1); //Bit6消隐
do Bus = 1; while(--i); //延时768us
do Bus = 0; while(--i); //延时768us
Bus = 1;
Sdat = LED_font[Disp_buf[Dig++]]; //获取显示数据
Send_bit(Sdat & 0x01); //发送位0
Send_bit(Sdat & 0x02); //发送位1
Send_bit(Sdat & 0x04); //发送位2
Send_bit(Sdat & 0x08); //发送位3
Send_bit(Sdat & 0x10); //发送位4
Send_bit(Sdat & 0x20); //发送位5
Send_bit(Dig & 0x01); //发送位选1
Send_bit(Dig & 0x02); //发送位选2
while(--i); //延时512us
Send_bit(Sdat & 0x40); //发送位6
for (i = 7;i> 0;i--) Send_bit(1); //位6移至Dout
if (Dig == 3) Dig = 0;
}
/*===================================================================
延时 5ms 程序
===================================================================*/
void Delay_5ms()
{
while(!TF1);
TF1 = 0;
TH1 = (- 5000) / 256;
TL1 = (- 5000) % 256;
}
/*===================================================================
主程序
===================================================================*/
void main()
{
TMOD = 0x10; //定时器1，16位模式
TCON = 0xc0; //TR1=1;TF1=1;
while(1) //主循环
{
Bus_drive(); //显示总线驱动
Key_scan(); //检测按键
Delay_5ms(); //延时5MS
}
} |
阿莫论坛20周年了！感谢大家的支持与爱护！！
月入3000的是反美的。收入3万是亲美的。收入30万是移民美国的。收入300万是取得绿卡后回国，教唆那些3000来反美的！
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发表于 2009-2-5 19:38:24
楼主
