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发表于 2012-4-20 00:29:28
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本帖最后由 diannaoza 于 2012-4-20 00:33 编辑
发送数据时,也用“中断方式”,清除 TI 后,用另一个变量通知主函数,数据发送完毕。
接收数据时,使用“中断方式”,清除 RI 后,用一个变量通知主函数,收到新数据。
下面程序是不是上面两行的意思,我就相这样做,可惜我看不懂C语言,有好心人转成汇编就好了
#include <REG52.H>
sbit LED = P1^0;
unsigned char UART_buff;
uart_buff data 60h
bit New_rec = 0, Send_ed = 1, Money = 0;
new_rec bit 20h
send_ed bit 21h
money bit 22h
//----------------------------------------------
void main (void)
{
clr new_rec
setb send_ed
clr money
SCON = 0x50; //串口方式1, 8-n-1, 允许接收.
mov SCON,#0X50
TMOD = 0x20; //T1方式2
MOV TMOD,#0X20
TH1 = 0xFD; //9600bps@11.0592MHz
MOV TH1,#0FDH
TL1 = 0xFD;
MOV TL1,#0FDH
TR1 = 1;
SETB TR1
ES = 1; //开中断.
SETB ES
EA = 1;
SETB EA
while(Money == 0); //等着交费,呵呵,等着接收$.
jnb money,$
while(1) {
while:
if ((New_rec == 1) && (Send_ed == 1)) { //如果收到新数据及发送完毕
jnb new_rec while_ex
jnb send_ed while_ex
while_enter:
mov sbuf,uart_buff
SBUF = UART_buff; //那就发送.
New_rec = 0;
clr new_rec
Send_ed = 0;
clr send_ed
while_ex:
ljmp while
} }
}
//----------------------------------------------
void ser_int (void) interrupt 4
{
if(RI == 1) { //如果收到.
jnb ri,ri_ex
RI = 0; //清除标志.
clr ri
New_rec = 1;
setb new_rec
UART_buff = SBUF; //接收.
mov uart_buf,sbuf
if(UART_buff == '1') LED = 1;
cjne uart_buf,#01h,ri_fn1ex
setb p1.0
ljmp ri_et_ex
ri_fn1ex:
if(UART_buff == '0') LED = 0;
cjne uart_buf,#00h,ri_fn2ex
clr p1.0
ljmp ri_et_ex
ri_fn2ex:
if(UART_buff == '$') Money = 1;
cjne uart_buf,#'$',ri_fn3ex
setb money
ljmp ri_et_ex
ri_fn3ex:
ri_et_ex:
ljmp ri_ti_ex
}
ri_ex:
else { //如果送毕.
TI = 0; //清除标志.
clr ti
Send_ed = 1;
setb send_ed
}
ri_ti_ex:
} |
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